Answer:
the graph of f(x) is {5 - (-2)) units, or 7 units, higher than that of g(x)
Step-by-step explanation:
The vertex form of a quadratic equation is y = a(x - h)^2 + k. (h, k) represents the vertex.
Comparing the given f(x) = -3(x-1)^2 to the above general form, we see that h = 1 and k = 2.
Comparing the given g(x) = -3(x-1)^2 to the above general form, we see that h = 1 and k = -5.
Thus, the x-coordinates of the vertex in both cases are the same: 1. The y-coordinates differ: for f(x), k = 2. and for g(x), k = -5.
Changing the k value translates the graph up or down.
In this case we see that the graph of f(x) is {5 - (-2)) units, or 7 units, higher than that of g(x).
