Respuesta :
Answer:
The answer is "Option A"
Explanation:
Energy stored in capcitor[tex]=\frac{1}{2}\ cv^2[/tex]
For point A:
[tex]C_A=\frac{\varepsilon_0 2A}{\frac{d}{2}}=\frac{4\ \varepsilon_0 A}{d}\\\\[/tex]
For point B:
[tex]C_B=\frac{\varepsilon_0 2A}{2d}=\frac{\varepsilon_0 A}{d}\\\\[/tex]
For point C:
[tex]C_c=\frac{\varepsilon_0 A}{d}\\\\[/tex]
For point D:
[tex]C_D=\frac{\varepsilon_0 A}{2 \frac{d}{2}}=\frac{\varepsilon_0 A}{d}\\\\[/tex]
For point E: [tex]C_E=\frac{\varepsilon_0 A}{2 \times 2d}=\frac{\varepsilon_0 A}{4d}\\\\[/tex]
therefore C_A has the maximum capacitance and max energy same energy is dir proportional to C for the same J
