Respuesta :

A. the first one is the answer

Step-by-step explanation:

[tex]\sf \bf {\boxed {\mathbb { a. \:2 {y}^{2} \sqrt{6x}}}}[/tex]

[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}[/tex]

[tex] \sqrt{4x {y}^{3} } \sqrt{6y} [/tex]

[tex] = \sqrt{4 \times 6 \: x \: {y}^{(3 + 1)} } [/tex]

[tex] = \sqrt{( {2})^{2} \times 6 \: x \: {y}^{4} } [/tex]

[tex] = \sqrt{( {2})^{2} \times 6 \: x \: { ({y}^{2} })^{2} } [/tex]

[tex] = 2 {y}^{2} \sqrt{6x} [/tex]

[tex]\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{❦}}}}}[/tex]