brookbarral3777
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PLEASE HELP!!!!!!
The average number of drops of NaHCO3 in the titration lab was 142. Calculate the number of moles of NaCHO3 that were required to neutralize the CH3COOH in the vinegar.
- 1 mole of acetic acid was required for 2 moles of sodium bicarbonate
- 1 mole of acetic acid was required for 1 mole of sodium bicarbonate
- 2 mole of acetic acid was required for 1 mole of sodium bicarbonate
- 1 mole of acetic acid was required for 3 mole of sodium bicarbonate

Respuesta :

Answer: The correct option is 1 mole of acetic acid was required for 2 moles of sodium bicarbonate

Explanation:

We are given:

Average number of drops of sodium bicarbonate = 142

The chemical equation for the reaction of sodium bicarbonate and acetic acid in vinegar follows:

[tex]NaHCO_3+CH_3COOH\rightarrow CH_3COONa+H_2CO_3[/tex]

From the stoichiometry of the reaction:

1 mole of sodium carbonate reacts with 1 mole of acetic acid in vinegar.

Hence, the correct option is 1 mole of acetic acid was required for 2 moles of sodium bicarbonate

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