Help please, my 2nd time asking this question.

(1 / 4) + (1 / 2)
= (1 / 4) + {(1 × 2) / (2 × 2)}
= (1 / 4) + (2 / 4)
= 1 + (2 / 4)
= 3 / 4
(1 / 2) + (3 / 8)
= {(1 × 4) / (2 × 4)} + 3 / 2
= (4 / 8) + (3 / 8)
= (4 + 3) / 8
= 7/8
Answer:
#3 is [tex]\frac{3}{4}[/tex] #4 is [tex]\frac{7}{8}[/tex]
Step-by-step explanation:
you must find a common denominator in both problems.
For #3 the common denominator is 4 so you would multiply [tex]\frac{1}{2}[/tex] by [tex]\frac{2}{2}[/tex] to get [tex]\frac{2}{4}[/tex] then add the numerators together to get 3 and the denominator stays 4.
[tex]\frac{1}{4} + \frac{2}{4} = \frac{3}{4}[/tex]
For #4 the common denominator is 8 so you would multiply [tex]\frac{1}{2}[/tex] by [tex]\frac{4}{4}[/tex] to get [tex]\frac{4}{8}[/tex]
then add the numerators together to get 7 and denominator stays 8.
[tex]\frac{4}{8} + \frac{3}{8} = \frac{7}{8}[/tex]