Answer:
CH2=CH-CH3
Explanation:
One of the ways of preparing alkenes is by dehydration of alcohols using sulphuric acid. The sulphuric acid merely acts as a catalyst in the process.
It begins with the protonation of the -OH group. This is followed by loss of water molecule since water is a good leaving group.
Loss of a proton now completes the mechanism and regenerates the acid catalyst.
The mechanism of dehydration of 2-propanol as well as the product formed in the process is shown in the image attached to this answer.
