The required solution after three successive iterations is near x = 7/8. Option c is correct.
Equation is -2x + 6 = -(2/3)^x + 5. Approximate the solution to the equation above using three iterations of successive approximation.
The equation is the values of two expressions that are equal.
Here,
[tex]-2x + 6 = -(2/3)^x + 5[/tex]
Arranging the equation
[tex]-2x + 6 +(2/3)^x - 5 = 0\\(2/3)^x-2x+1=0[/tex]
Since the solution of the equation is when f(x) = 0 at near to x = 0.8
[tex]f(x) = (2/3)^x-2x+1\\[/tex]
First iteration at x =0.8
[tex]f(0.8) = (2/3)^x-2x+1\\ = (2/3)^{0.8}-2*0.8+1\\ = 0.123[/tex]
It will go up more to get exact zero, so
Second iteration at x = 0.9
[tex]f(0.9) = (2/3)^{0.9}-2*0.9+1\\f(0.9) = -0.106[/tex]
It seems that zero is near 0.9 so will go down
The third iteration at x = 0.87
[tex]f(0.87) = (2/3)^{0.87}-2*0.87+1\\f(0.87) = -0.037[/tex]
Here , solution is much near to x = 0.87 or x =7/8.
Thus, the required solution after three successive iterations is near x = 7/8.
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