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A pressure cooker contains 5.68 L of air at a temperature of 390 4K if the absolute pressure of the air in the pressure cooker is 205 Pa how many moles of air are in the cooker

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Answer:

3.59x10⁻⁴ mol

Explanation:

Assuming ideal behaviour we can solve this problem by using the PV=nRT formula, where:

  • P = 205 Pa
  • V = 5.68 L
  • n = ?
  • R = 8314.46 Pa·L·mol⁻¹·K⁻¹
  • T = 390.4 K

We input the data given by the problem:

  • 205  Pa * 5.68 L = n * 8314.46 Pa·L·mol⁻¹·K⁻¹ * 390.4 K

And solve for n:

  • n = 3.59x10⁻⁴ mol

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