contestada

Suppose that 45% of all babies born in a particular hospital are girls. If 7 babies born in the hospital are randomly selected, what is the probability that at most of them are girls?

Respuesta :

Tundexi

Answer:

0.10

Explanation:

Using the binomial probability formula: P(X = x) = (nCx) * p^x * (1 - p)^(n-x)

P(X≤1) = P(X = 0) + P(X = 1)

P(X≤1) = (7C0) * 0.45^0 * (0.55)^7 + (7C1) * 0.45^1 * (0.55)^6

P(X≤1) = 0.1024

P(X≤1) = 0.10

So, the Probability that at most one of them are girls 0.10.

Otras preguntas