Answer:
The smaller number is 4√2 and the larger number is (4√2 + 1).
Step-by-step explanation:
Let the two numbers be x and y, where y is the larger of the two numbers.
Since y is the larger number, it is one more than the smaller number. So:
[tex]y=x+1[/tex]
When negative two times the smaller is added to the square of the larger, the result is 33. In other words:
[tex]-2x+y^2=33[/tex]
Substitute:
[tex]-2x+(x+1)^2=33[/tex]
Solve for x. Square:
[tex]-2x+(x^2+2x+1)=33[/tex]
Simplify:
[tex]x^2+1=33[/tex]
Subtract one from both sides:
[tex]x^2=32[/tex]
And take the square root of both sides:
[tex]x=\pm\sqrt{32}=\pm 4\sqrt{2}[/tex]
Since y is positive, we can ignore the negative case. So, the smaller number is:
[tex]x=4\sqrt{2}\approx5.66[/tex]
And the larger number is:
[tex]y = 4\sqrt{2} + 1 \approx6.66[/tex]
