Answer:
a) csc∅ = √53/2
b) cot ∅ = 15/√514
Step-by-step explanation:
a) The value of cot ∅ = -7/2
cos ∅ < 0
We note that cos(∅) is less than 0 in Quadrant II and III, and cot(∅) is less than 0 in the Quadrant II, therefore, we have;
∅ is in the Quadrant II
csc∅ = (√((-7)² + 2²))/2 =√53/2 ≈ 3.64
csc∅ = √53/2
b) cos∅ 15/17
∅ is in Quadrant IV
∴ cot ∅ = 15/(√(15² + 17²)) = 15/√514 ≈ 0.662
cot ∅ = 15/√514
