Answer:
All real numbers are solutions.
Step-by-step explanation:
Our goal is to isolate "v" on one side of the equation. Let's do this step by step.
5(v+1)−v=4(v−1)+9
Step 1: Simplify both sides of the equation.
5(v + 1) − v = 4(v−1) + 9
(5)(v) + (5)(1) + −v = (4)(v) + (4)(−1) + 9(Distribute)
5v + 5 + −v = 4v + −4 + 9
(5v + −v) +(5) = (4v) + (−4 + 9) (Combine Like Terms)
4v + 5 = 4v + 5
4v + 5 = 4v + 5
Step 2: Subtract 4v from both sides.
4v + 5 − 4v = 4v + 5 − 4v
5 = 5
Step 3: Subtract 5 from both sides.
5 − 5 = 5 − 5
0 = 0
This means that all real numbers are solutions.
Any real number could be "v."
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