An assembly line consists of 21 tasks grouped into 5 workstations. The sum of the 21 task times is 85 minutes. The largest assigned cycle time is 20 minutes. What is the efficiency of this line

Respuesta :

Answer:

The efficiency of this line is 0.85 = 85%.

Step-by-step explanation:

Efficiency:

The efficiency is given by the following formula:

[tex]E = \frac{T_t}{tn}[/tex]

In which [tex]T_t[/tex] is the total task time, [tex]t[/tex] is the largest assigned cycle time and n is the number of workstations.

5 workstations

This means that [tex]n = 5[/tex]

The sum of the 21 task times is 85 minutes.

This means that [tex]T_t = 85[/tex]

The largest assigned cycle time is 20 minutes.

This means that [tex]n = 20[/tex]

What is the efficiency of this line?

[tex]E = \frac{T_t}{tn} = \frac{85}{20*5} = \frac{85}{100} = 0.85[/tex]

The efficiency of this line is 0.85 = 85%.