Respuesta :
Answer:
100% probability that the loss in nominal dollars is less than 1000, given that the loss in nominal dollars is greater than 200.
Step-by-step explanation:
Uniform probability distribution:
An uniform distribution has two bounds, a and b.
The probability of finding a value of at lower than x is:
[tex]P(X < x) = \frac{x - a}{b - a}[/tex]
The probability of finding a value between c and d is:
[tex]P(c \leq X \leq d) = \frac{d - c}{b - a}[/tex]
The probability of finding a value above x is:
[tex]P(X > x) = \frac{b - x}{b - a}[/tex]
Uniformly distributed on [0, 1000].
This means that [tex]a = 0, b = 1000[/tex]
Given that the loss in nominal dollars is greater than 200.
This means that [tex]a = 200[/tex]
Calculate the probability that the loss in nominal dollars is less than 1000
[tex]P(X < x) = \frac{x - a}{b - a}[/tex]
[tex]P(X < 1000) = \frac{1000 - 200}{1000 - 200} = 1[/tex]
100% probability that the loss in nominal dollars is less than 1000, given that the loss in nominal dollars is greater than 200.