Reaction of 2,3-dimethyl-1-butene with HBr leads to an alkyl bromide, C6H13Br. On treatment of this alkyl bromide with KOH in methanol, elimination of HBr occurs and a hydrocarbon that is isomeric with the starting alkene is formed. What is the structure of this hydrocarbon, and how do you think it is formed from the alkyl bromide

Question

22-06-2021
Chemistry

contestada

Reaction of 2,3-dimethyl-1-butene with HBr leads to an alkyl bromide, C6H13Br. On treatment of this alkyl bromide with KOH in methanol, elimination of HBr occurs and a hydrocarbon that is isomeric with the starting alkene is formed. What is the structure of this hydrocarbon, and how do you think it is formed from the alkyl bromide

Respuesta :

Otras preguntas

how has the value of salt changed from the time of the ancient romans to today

Fernando is starting a new sales job, and needs to decide which of two salary plans to choose from. For plan A, he will earn $100/week plus 15% commission on al

Which sentence from part 5 of The Call of the Wild would best serve as evidence of the theme "one’s natural instincts can be extremely powerful"? And here, lyin

Completely factor the following expression t^2+4tv+4^2

solve the following logarithm:log 1/3 27

Nicole run,runs,running,are running three miles every morning What's the right answer

A train that is 1 mile long starts through a tunnel that is also 1mile long . The train is traveling 15 miles per hour. How long does it take for the train to g

Describe a real-world situation that could be modeled by dividing two rational numbers.

It takes a boat 4 h to travel 75 km downstream. Let x represent the boat’s speed in still water, and let y represent the water’s current in kilometers per hour.

1. Forrest is purchasing a car priced at $7,299. His down payment is $299 and his monthly payments are $165 per month for 48 months. The deferred cost of the

pstnonsonjoku pstnonsonjoku · Answer 1 · 2021-06-24T04:58:00+02:00

Answer:

See explanation and image attached

Explanation:

The image attached shows the entire scheme of reactions mentioned in the question.

The first reaction is an addition reaction which yields a tertiary alkyl halide as shown in accordance with Markovnikov rule.

The second reaction is a dehydrohalogenation in which the base abstracts a proton from the alkyl halide followed by loss of a bromide ion to yield the corresponding alkene.

This alkene is an isomer of the starting material.