Answer:
[tex]Pr = 0.0479[/tex]
Step-by-step explanation:
Given
[tex]p =23\%[/tex] --- proportion of completed passes
Required
The probability that he has 6 incomplete before he has 1 completion
Let:
[tex]q \to[/tex] proportion of back passes not completed
Using complement rule:
[tex]q = 1 - p[/tex]
[tex]q = 1 - 23\%[/tex]
[tex]q = 1 - 0.23[/tex]
[tex]q = 0.77[/tex]
The event that he has 6 incomplete passes before he completed one is:
q q q q q q p
And the probability is:
[tex]Pr = q * q * q * q * q * q * p[/tex]
[tex]Pr = q^6* p[/tex]
[tex]Pr = 0.77^6* 0.23[/tex]
[tex]Pr = 0.0479[/tex]
