Solution :
Given that there is only one set which can contain all the five correct answers. While guessing that I am likely to choose only one sequence of the answers as another, then the probability of getting all the five answers correct is given by :
Given : X [tex]\sim[/tex] binomial [tex]$\left( 5 , \frac{1}{3} \right)$[/tex]
P (X = 5)
[tex]$= \ ^5C_5\left({\frac{1}{3}\right)^5\left(\frac{2}{3}\right)^0$[/tex]
= 0.00412
Thus the probability is 0.00412
