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A ball is thrown into the air with a velocity of 39 ft/s. Its height, in feet, after t seconds is given by s(t) = 39t − 16t2. Find the velocity (in ft/s) of the ball at time t = 1 second.

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asuwafohjames

Answer:

7 ft/s

Explanation:

Applying,

V(t) = ds(t)/dt

Where V(t) = velocity of the ball at a given time

From the question,

Given: s(t) = 39t-16t²

Therefore,

V(t) = ds(t)/dt = 39-32t............. Equation 1

at t = 1 seconds,

Substitute the value of t into  equation 1

V(t) = 39-32(1)

V(t) = 39-32

V(t) = 7 ft/s

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