Respuesta :
Answer:
0.9988 = 99.88% probability that the mean number of years between asbestos exposure and death will be between 22 and 29 years.
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
The mean number of years between asbestos exposure and death is found to be 25 years with a standard deviation of 7 years in a particular county
This means that [tex]\mu = 25, \sigma = 7[/tex]
Sample of 50:
This means that [tex]n = 50, s = \frac{7}{\sqrt{50}}[/tex]
What is the probability that the mean number of years between asbestos exposure and death will be between 22 and 29 years?
This is the p-value of Z when X = 29 subtracted by the p-value of Z when X = 22.
X = 29
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{29 - 25}{\frac{7}{\sqrt{50}}}[/tex]
[tex]Z = 4.04[/tex]
[tex]Z = 4.04[/tex] has a p-value of 1.
X = 22
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{22 - 25}{\frac{7}{\sqrt{50}}}[/tex]
[tex]Z = -3.03[/tex]
[tex]Z = -3.03[/tex] has a p-value of 0.0012.
1 - 0.0012 = 0.9988
0.9988 = 99.88% probability that the mean number of years between asbestos exposure and death will be between 22 and 29 years.
