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A sample of gas has a volume of 100. L at 17 °C and 800. torr. To what temperature must the gas be cooled in order for its volume to become 50.0 L at a pressure of 600. torr? Your answer will need to be in Kelvin.

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maacastrobr

Answer:

108.81 K

Explanation:

First convert 17 °C to Kelvin:

  • 17 + 273.16 = 290.16 K

Assuming ideal behaviour, we can solve this problem by using the combined gas law, which states that at constant composition:

  • P₁V₁T₂=P₂V₂T₁

Where in this case:

  • P₁ = 800 torr
  • V₁ = 100 L
  • T₂ = ?
  • P₂ = 600 torr
  • V₂ = 50 L
  • T₁ = 290.16 K

We input the data:

  • 800 torr * 100 L * T₂ = 600 torr * 50 L * 290.16 K

And solve for T₂:

  • T₂ = 108.81 K

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