How much should Sheila deposit in a savings account at 8% simple interest in order to
have a balance of $3,000 after six months?

Respuesta :

Answer:  2884.62 dollars

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How to get that answer:

Because Sheila is dealing with simple interest, the formula to use is

A = P*(1+r*t)

where,

  • A = final amount
  • P = amount to deposit (aka principal)
  • r = annual interest rate in decimal form
  • t = number of years

In this case,

  • A = 3000
  • P = unknown
  • r = 0.08
  • t = 6/12 = 0.5 (since 6 months is half a year)

So,

A = P*(1+r*t)

3000 = P*(1+0.08*0.5)

3000 = P*(1+0.04)

3000 = P*(1.04)

3000/(1.04) = P

2884.61538 = P

P = 2884.61538

P = 2884.62

We round to the nearest cent, aka nearest hundredth.

Sheila needs to deposit $2,884.62