I NEED HELP ASAP 30 POINTS - GEOMETRY

2. The general form of a circle is given as x^2 + y^2 + 6x – 14y + 33 = 0
(a) What are the coordinates of the center of the circle? Show all your work.
(b) What is the length of the radius of the circle? Show all your work.
Answer:

I NEED HELP ASAP 30 POINTS GEOMETRY 2 The general form of a circle is given as x2 y2 6x 14y 33 0 a What are the coordinates of the center of the circle Show all class=

Respuesta :

Answer:

Center = (-3,  7)

radius = 5

Step-by-step explanation:

x² + y² + 6x – 14y + 33 = 0

Put the equation in standard form:

(x - h)² + (y - k)² = r²

(h, k) is the center

r is the radius

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Regroup

x² + 6x + y² - 14y = -33

Complete the square for x

(x + 3)² + (y - 7)² = -33 + 3² + (-7)²

(x + 3)² + (y - 7)² = 25

Center = (h, k) = (-3,  7)

radius = √25 = 5