PLEASE PLEASE HELP ME WITH THIS GEOMETRY QUESTION!!!


Step-by-step explanation:
Objective: Circle Theorems
The arcs add up to 360 and they are in proportion so
[tex]3x + 3x + 4x + 5x = 360[/tex]
[tex]15x = 360[/tex]
[tex]x = 24[/tex]
So this means that Arc AB and BC measure is 72 each. Arc CD measure is 96 and Arc DA measures is 120.
Angle 1 measure is a inscribed angle of Arc CD.
So it measures
[tex] \frac{96}{2} = 48[/tex]
Angle 2 is a inscribed angle of Arc AB so it measures
[tex] \frac{72}{2} = 36[/tex]
Angle 3 is a inscribed angle of Arc DA.
[tex] \frac{120}{2} = 60[/tex]
Angle 4 is a inscribed angle of Arc BC so it measures
[tex] \frac{72}{2} = 36[/tex]
Angle 5 is formed by tangent line ED. Since D lies on the circumference, it also is tangent to point e so it also measures 90 degrees.
Angle 4 measures 32 so Angle 5 is it complement to Angle 4.
[tex]32 + x = 90[/tex]
[tex]x = 58[/tex]
Angle 6 is formed by two intersecting chrods
so it measures
[tex] \frac{1}{2} (120+ 72) = 96[/tex]