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A 0.50 kg croquet ball is initially at rest on the grass. When the ball is
struck with a croquet mallet, the average force exerted on the ball is 230
N. If the ball's speed after being struck is 3.2 m/s. (a) Calculate the change
in the momentum and (b) the time during which the momentum was
changed, of the croquet ball ? *

Respuesta :

Numenius

Answer:

(a) 1.6 Ns

(b) 6.95ms

Explanation:

mass of ball, m = 0.5 kg

initial velocity, u = 0

force, F = 230 N

final speed, v = 3.2 m/s

(a) According to the formula of momentum

The change in momentum = m (v - u) = 0.5 (3.2 - 0) = 1.6 Ns

(b) According to the Newton's second law, the force acting on the ball is rate of change of momentum of ball. let the time is t.

[tex]F =\frac{m(v-u)}{t}\\\\230 =\frac{1.6}{t}\\\\t =6.95\times 10^{-3} s = 6.95 ms[/tex]

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