Answer:
a). 1.05 Elanor's standardized score
b). 1.04 Gerald's standardized score
Step-by-step explanation:
According to the Question,
Thus, Elanor's standardized score is
[tex]Z=\frac{x-mean}{standard deviation}[/tex]
Z = (680-569) ÷ 106 ⇒ 111/106 ⇒ 1.047≈1.05
Thus, Gerald's standardized score is
[tex]Z=\frac{x-mean}{standard deviation}[/tex]
Z = (27-24.5) ÷ 2.4 ⇒ 2.5/2.4 ⇒ 1.041≈1.04