Answer:
Step-by-step explanation:
Given the line is parallel to y = 2x - 7
Therefore, the slope = 2
Find equation of line passing through ( 4, 6 ) and slope 2
[tex](y - q) = m(x -p) \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ [ \ where \ p = 4 \ , q = 6 \ ]\\\\(y - 6 ) = 2 ( x - 4) \\\\y = 2x - 8 + 6 \\\\y = 2x - 2[/tex]
x - intercept of y = 2x - 7 :
Putting y = 0 => 0 = 2x - 7
2x = 7
[tex]x = \frac{7}{2}[/tex]
Therefore x intercept
[tex]=( \frac{7}{2} , 0)[/tex]
x - intercept of y = 2x - 2
Putting y = 0 => 0 = 2x - 2
2x = 2
x = 1
Therefore x intercept
[tex]= ( 1 , 0 )[/tex]
