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Spin cycles of washing machines remove water from clothes by producing a large radial acceleration at the rim of the cylindrical tub that holds the water and clothes. Suppose that the diameter of the tub in a typical home washing machine is 50 cm.

Required:
What is the rotation rate, in rev/min, of the tub during the spin cycle if the radial acceleration of points on the tub wall is 3g?

Respuesta :

Numenius

Answer:

The rate of rotation is 1123.6 rpm.

Explanation:

diameter of tub =50 cm

radius of tub, r = 25 cm = 0.25 m

Acceleration, a = 3 g

The centripetal acceleration is given by

[tex]a = r w^2\\\\3\times 9.8 =0.25 \times w^2\\\\w = 117.6 rad/s\\\\w = 2\pi n \\\\117.6 = 2\times 3.14 \times n\\\\n = 18.73 rps = 1123.6 rpm[/tex]

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