In how many ways could members of the following club line up all 9 members for a photograph?
N={Carl, Lisa, Jen, Adam, David, Cathy, Evelyn, Alan, Bill}
way(s)
(Simplify your answer.)

Respuesta :

Answer:

N! = 362,880

There are 9 factorial ways because there are 9 choices for position 1,  8 choices for position 2, 7 choices for position 3, etc.

Members could line up in 3, 62,800 ways

What is factorial?

The product of all positive integers less than or equal to n in mathematics is known as the factorial of a non-negative integer, indicated by the symbol n!. Additionally, the factorial of n is equal to the sum of n and the subsequent smaller factorial: For instance, According to the convention for an empty product, the value of 0! is 1.

Given

members =9

members can line up in any way..Since there are 9 places.

The 1st member can stand in any of the 9 places, so he can stand in 9 ways.

2nd member can stand in the remaining 9-1 places in 9-1 = 8 ways

3rd member can stand in the remaining 8-1 places in 8-1 = 7 ways

4th member can stand in the remaining 7-1 places in 7-1 = 6 ways

5th member can stand in the remaining 6-1 places in 6-1 = 5 ways

6th member can stand in the remaining 5-1 places in 5-1 = 4 ways

7th member can stand in the remaining 4-1 places in 4-1 = 3 ways

8th member can stand in the remaining 3-1 places in 3-1 = 2 ways

9th member can stand in the remaining 2-1 places in 2-1 = 1 ways

Total no. of ways members can stand = n! = 9! = 9*8*7*6*5*4*3*2*1 = 362800

to learn more about factorial refer to:

https://brainly.com/question/24115376

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