Answer:
Eleanor and Harold
Step-by-step explanation:
The decimal [tex]0.13\overline{7}[/tex] consists of the sum of two terminating decimals and one non-terminating decimal:
[tex]0.13\overline{7}=0.1+0.03+0.00\overline{7}[/tex]
Therefore, we have:
[tex]0.13\overline{7}=\frac{1}{10}+\frac{3}{100}+\frac{7}{900},\\\\0.13\overline{7}=\frac{10}{100}+\frac{3}{100}+\frac{7}{900},\\\\0.13\overline{7}=\frac{13}{100}+\frac{7}{900}=\frac{117}{900}+\frac{7}{900}=\boxed{\frac{124}{900}}[/tex]
Hector's answer is equivalent but not simplified. However, they are both technically correct.
