Answer:
first u will find de L.C.M which is 6
so u will multiply de whole equation by 6 hence
6(x/3)- 6(x-1/ 2) greater or equal to 6(1)
u will then cancel getting de equation to be
2(x)-3(x-1) greater or equal to 6 (1)
now, u will expand de equation
2x-3x+3 greater or equal to 6
now u group like terms
2x-3x greater or equal to 6-3
hint: greater or equal to must be done with it's symbol
so now for de answer, u will get -x greater or equal to 3
wen u get this, u change de operation to be opposite of de current sign
now de final answer becomes
