Solution :
Given :
Equation :
y = 6.3333 x + 53.0298
Here, x = number of hours studied
y = the exam score
a). To predict the exam score, we have to replace x in the least square regression line by 2 :
y = 6.3333 x + 53.0298
y = 6.3333 (2) + 53.0298
= 65.6964
Thus he predicted exam score is 65.6964
b). The slope is the co-efficient of x in the least squares regression line :
Slope = 6.3333
The slope represents the average increase in y as x increases by 1.
The exam score increases on average by 6.3333 points per hour studied.
c). The mean score of the [tex]\text{ students who did not study}[/tex] (studied 0 hours) is obtained by replacing x in the least squares regression line by 0 :
y = 6.3333 x + 53.0298
y = 6.3333 (0) + 53.0298
= 53.0298
d). To predict the exam score of a student who studied 5 hours, we replace x in the least squares regression line by 2 :
y = 6.3333 x + 53.0298
y = 6.3333 (5) + 53.0298
y = 84.6963
Thus the average exam score of a student who studied 5 hours is 84.6963
Since the actual exam score 81 is less than the average exam score of 84.6963 the student's exam score is below the average.