Note: Please show all work and calculation setups to get full credit. T. he following may be used on this assignment: specific heat of (water=4.184 J/g oC; ice=2.03 J/g oC; steam=1.99 184 J/g oC); heat of fusion of water=80. cal/g; heat of vaporization=540 cal/g; 1cal=4.184J.
Calculate the energy required (in J) to convert 25 g of ice at -15 oC to water at 75 oC.

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dsdrajlin dsdrajlin · Answer 1 · 2021-06-29T02:40:43+02:00

Answer:

1.7 × 10⁴ J

Explanation:

Step 1: Calculate the heat required to raise the temperature of ice from -15 °C to 0°C

We will use the following expression.

Q₁ = c(ice) × m × ΔT

Q₁ = 2.03 J/g.°C × 25 g × [0°C - (-15°C)] = 7.6 × 10² J

Step 2: Calculate the heat required to melt 25 g of ice

We will use the following expression.

Q₂ = C(fusion) × m

Q₂ = 80. cal/g × 25 g × 4.184 J/1 cal = 8.4 × 10³ J

Step 3: Calculate the heat required to raise the temperature of water from 0°C to 75 °C

We will use the following expression.

Q₃ = c(water) × m × ΔT

Q₃ = 4.184 J/g.°C × 25 g × (75°C - 0°C) = 7.8 × 10³ J

Step 4: Calculate the total heat required

Q = Q₁ + Q₂ + Q₃

Q = 7.6 × 10² J + 8.4 × 10³ J + 7.8 × 10³ J = 1.7 × 10⁴ J