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Urgent: Suppose that 14.9 mL of HNO3 is neutralized by 53.1 mL of a 0.0048 M solution of KOH in a titration. Calculate the concentration of the HNO3 solution.

Urgent Suppose that 149 mL of HNO3 is neutralized by 531 mL of a 00048 M solution of KOH in a titration Calculate the concentration of the HNO3 solution class=

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Answer:

0.017 M

Explanation:

The reaction that takes place is:

  • HNO₃ + KOH → KNO₃ + H₂O

First we calculate how many KOH moles reacted, using the given volume and concentration:

  • 53.1 mL * 0.0048 M = 0.255 mmol

As 1 mmol of KOH reacts completely with 1 mmol of HNO₃, in 14.9 mL of the HNO₃ solution there were 0.255 HNO₃ mmoles.

With that in mind we can calculate the concentration of the HNO₃ solution using the calculated number of moles and given volume:

  • 0.255 mmol / 14.9 mL = 0.017 M