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10 An object weighing 1 kilogram is thrown straight up 10 meters in the air. What is the kinetic energy of the object when it reaches the highest point in its path?
F. 0J
G .9.8 )
H .98 )
J .102 )​

Respuesta :

machmillerg

Answer:

F. 0J

Explanation:

At the objects highest point in the trajectory the KE = 0 since this trajectory is completely vertical with no x-component but its PE would be greatest at this point.

KE = (1/2)mv²

KE = 0; because velocity equals 0

PE = m*g*h

PE = 1kg*(9.81m/s^2)*10m

PE = 98.1J

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