SOMEONE, PLEASE HELP!!!!!!

Answer:
I think its y^-3
Step-by-step explanation:
Since y^-3/y^-2 are both negatives they would swap places to become positive - y^2/y^3
then using rules of exponents you would subtract the exponents witch would be y^-3
Answer:
[tex]\frac{1}{y^{3} }[/tex]
Step-by-step explanation:
[tex]\frac{y^{-5}}{y^{-2}}[/tex]
Apply exponent rule [tex]\frac{x^a}{x^b}=x^{a-b}[/tex]
[tex]=y^{-5-\left(-2\right)}[/tex]
Apply rule [tex]-\left(-a\right)=a[/tex]
[tex]=y^{-5+2}[/tex]
Add/Subtract the numbers -5+2=-3
[tex]=y^{-3}[/tex]
Apply exponent rule [tex]a^{-b}=\frac{1}{a^b}[/tex]
[tex]=\frac{1}{y^3}[/tex]