A car starts from the state of xestIf its velocity becomes 70 km/hr in 6 minutes, i) what is the accordine acceleration of F the car? (ii) what is the the distance cover ded by the car?​

Respuesta :

Answer: [tex]3.5\ km[/tex]

Explanation:

Given

Car starts from the state of rest and acquires a velocity of [tex]70\ km/hr[/tex] in 6 minutes

Final velocity in m/s is [tex]v=70\approx 19.44\ m/s[/tex]

Using equation of motion

[tex]v=u+at\\\Rightarrow 19.44=0+a(6\times 60)\\\Rightarrow a=0.054\ m/s^2[/tex]

Distance covered in 360 s

[tex]\Rightarrow v^2-u^2=2as\\\Rightarrow 19.44^2-0=2\times 0.054\times s\\\Rightarrow s=3500.64\ m\approx 3.5\ km[/tex]