Answer:
[tex]P(x\geq 1) = 0.923[/tex]
Step-by-step explanation:
From the question we are told that:
Percentage of student to get A [tex]P(A)=\%5=0.05[/tex]
Sample size [tex]n=50[/tex]
Generally Number of student to get A is
[tex]N_a=n*P(A)[/tex]
[tex]N_a=50*0.05[/tex]
[tex]N_a=2.5[/tex]
Therefore
Probability that one student gets an A grade is mathematically by
[tex]^nPC_xP^x(1-P)^{n-x}[/tex]
[tex]P(x\geq 1)=1-P(x<1)[/tex]
[tex]P(x\geq 1) =1-P(x=0)[/tex]
[tex]P(x\geq 1) =^50C_0(0.05)^0(0.95)^50[/tex]
[tex]P(x\geq 1) = 0.923[/tex]
