Respuesta :

aayushdubey333

Answer:

Given that 3/7 + (- 6/11) + (- 8/21) + (5/22)

Taking L.C.M. of the denominators 7, 11, 21 and 22 and then solving it.

L.C.M. of 7, 11, 21 and 22 = 2 x 3 x 7 x 11 = 462

= (462/7) x 3 – (462/11) x 6 – (462/21) x 8 + (462/22) x 5

= (198/462) – (252/462) – (176/462) + (105/462)

= (303/462) – (428/462)

= (-125/462)

sreedevi102

Answer:

[tex]-\frac{125}{462}[/tex]

Step-by-step explanation:

[tex]\frac{3}{7} + ( - \frac{6}{11}) + ( -\frac{8}{21}) + \frac{5}{22}\\\\\frac{3}{7} - \frac{6}{11} -\frac{8}{21} + \frac{5}{22}\\\\(\frac{3}{7} -\frac{8}{21})+ (\frac{5}{22} - \frac{6}{11}) \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ [\ arranging \ the \ terms \ for \ easy \ calculation \ ] \\\\(\frac{(3 \times 3) - 8}{21}) + \frac{5 - ( 6 \times 2)}{22}\\\\\frac{9-8}{21} + \frac{5-12}{22}\\\\\frac{1}{21} + \frac{-7}{22}\\\\\frac{1}{21} - \frac{7}{22}\\\\\frac{(1 \times 22) - ( 7 \times 21)}{21 \times22}\\\\[/tex]

[tex]\frac{22-147}{462}\\\\-\frac{125}{462}[/tex]

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