contestada

A 35-gram stainless steel ball on a track is moving at a velocity of 9 m/s. On the same track, a 75-gram stainless steel ball is moving at a velocity of ā€“7 m/s. After colliding, the 35-gram ball moves at a velocity of ā€“15 m/s. Assume there is no net force on the system.

What is the velocity of the 75-gram ball after the collision? Round to the nearest tenth.

Respuesta :

chibunduoyibe

Explanation:

the answer is in the above image

Ver imagen chibunduoyibe

Given:

mass of first ball, m1 = 35g

mass of second ball, m2 = 75g

velocity of first ball before collision, u1 = 9m/s

velocity of second ball before collision, u2 = -7m/s

velocity of first ball after collision, v1 = -15m/s

velocity of second ball after collision, v2 = ? (To Find)

Now it is given that there is no net force on the system of two balls

according to the Law of Conservation of Momentum so, here momentum is constant before and after collision:

P1 = P2

m1u1 + m2u2 = m1v1 + m2v2

35g*9m/s + 75g*(-7m/s) = 35g*(-15m/s) + 75g*v2

v2 = (35g*9m/s + 75g*(-7m/s) - 35g*(-15m/s))/75g

v2 = 4.2m/s

therefore, the velocity of second ball after collision is 4.2m/s

What is the formula of conservation of momentum?

As a result, the equation of the law of conservation of momentum is as follows: m1 u1 + m2 u2 represents the total momentum of particles A and B before the collision, and m1 v1 + m2 v2 represents the total momentum of particles A and B after the collision.

What is momentum unit?

Momentum. If the mass of an object is m and it has a velocity v, then the momentum of the object is defined to be its mass multiplied by its velocity. momentum = mv. Momentum has both magnitude and direction and thus is a vector quantity. The units of momentum are kg m sāˆ’1 or newton seconds, N s.

Learn more about Law of Conservation of Momentum here

https://brainly.com/question/7538238

#SPJ2

Otras preguntas