Answer:
[tex]\theta=28.32 \textdegree[/tex]
Explanation:
From the question we are told that:
Width of opening [tex]w=74.0m[/tex]
Wavelength [tex]\lambda=35.1m[/tex]
Generally the equation for Angle is mathematically given by
Since the ocean diffracts
Therefore the relation
[tex]n\lambda=dsin\theta[/tex]
[tex]\theta=sin^{-1}(\frac{n\lambda}{d})[/tex]
Where
n =nth order minimal (n=1 for smallest safe angle)
Therefore
[tex]\theta=sin^{-1}(\frac{1*35.1}{74})[/tex]
[tex]\theta=28.32 \textdegree[/tex]
