Answer:
210 different mega calzones can be made.
Step-by-step explanation:
Fundamental counting principle:
States that if there are p ways to do a thing, and q ways to do another thing, and these two things are independent, there are p*q ways to do both things.
Additionally:
The order in which the toppings and the cheeses are chosen is not important, which means that the combinations formula is used to solve this question.
Combinations formula:
[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
Toppings:
5 from a set of 7. So
[tex]C_{7,5} = \frac{7!}{5!2!} = 21[/tex]
Cheeses
3 from a set of 6. So
[tex]C_{6,3} = \frac{6!}{3!3!} = 20[/tex]
How many different mega calzones can be made if a mega calzone contains 5 different toppings and 3 different cheeses?
Toppings and cheeses are independent, and thus, by the fundamental counting principle:
21*20 = 210
210 different mega calzones can be made.