Answer:
The magnitude of the force exerted on the ball by the racquet is 94.73 N.
Explanation:
The force exerted on the ball is the following:
[tex] F = ma [/tex]
Where:
m: is the mass of the ball = 59 g
a: is the acceleration
The acceleration of the ball can be found with the following kinematic equation:
[tex] v_{f}^{2} = v_{0}^{2} + 2ad [/tex]
Where:
d: is the distance = 0.36 m
[tex]v_{f}[/tex]: is the final speed = 34 m/s
[tex]v_{0}[/tex]: is the initial speed = 0 (it start from rest)
Hence, the acceleration is:
[tex] a = \frac{v_{f}^{2}}{2d} = \frac{(34 m/s)^{2}}{2*0.36 m} = 1605.6 m/s^{2 [/tex]
Finally, the force is:
[tex] F = ma = 59 \cdot 10^{-3} kg*1605.6 m/s^{2} = 94.73 N [/tex]
Therefore, the magnitude of the force exerted on the ball by the racquet is 94.73 N.
I hope it helps you!
