d. The equation of a line is y+6=-9(x - 1). The slope of the line is and the y-intercept is A point on the line is​

d The equation of a line is y69x 1 The slope of the line is and the yintercept is A point on the line is class=

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Answer: The equation of a line is y+6=-9(x-1). The slope of the line is -9 and the y-intercept is 3. A point on the line is (0, 3)

Step-by-step explanation:

Let's start by putting it in slope intercept form.

First use the distributive property

[tex]y+6=-9(x-1)\\y+6=(-9)(x)+(-9)(-1)\\y+6=-9x+9[/tex]

Now subtract 6 from both sides

[tex]y+6-6=-9x+9-6\\y=-9x+3[/tex]

Now it is in slope intercept form (y=mx+b)

In slope intercept form the slope of the line is the value m. In our equation the value m is -9 making that our slope.

In slope intercept form the y-intercept of the line is b. In our equation the value of b is 3 making that our y-intercept.

To find a point on the line we can sub x with any number to find the y so that we can find the coordinate.

[tex]y=-9(0)+3\\y=0+3\\y=3[/tex]

A point on the line is (0, 3)

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