Answer:
The decrease in decibels is 0.1 dB.
Explanation:
Let the intensity of one chorus is Io.
let the intensity of 1000 vocalist is dB.
The intensity of 1000 vocalist is 1000 Io.
[tex]dB = 10log\frac{1000Io}{Io}=30[/tex]..... (1)
let the intensity of 999 vocalist is dB'.
[tex]dB' = 10log\frac{999Io}{Io}=29.9[/tex]..... (2)
So, the change is
= dB - dB' = 30 - 29.9 = 0.1 dB