Answer:
3.50 × 10⁻³ g/L
Explanation:
Step 1: Make an ICE chart for the solution of SrCO₃
"S" represents the molar solubility.
SrCO₃(s) ⇄ Sr²⁺(aq) + CO₃²⁻(aq)
I 0 0
C +S +S
E S S
The solubility product constant (Ksp) is:
Ksp = [Sr²⁺] [CO₃²⁻] = S²
S = √Ksp = √5.60 × 10⁻¹⁰ = 2.37 × 10⁻⁵ M
Step 2: Convert "S" to g/L
The molar mass of SrCO₃ is 147.63 g/mol.
2.37 × 10⁻⁵ mol/L × 147.63 g/mol = 3.50 × 10⁻³ g/L
