The number of combinations possible if a 3-member committee has to be formed from 2 teachers and 2 parents is 4 combinations
Combination and permutation
Combinations have to do with selection compared to permutation that has to do with the arrangement.
If a 3-member committee has to be formed from 2 teachers and 2 parents, the total committee is given as:
Total committee members = 2 + 2
Total committee members = 4 committees
If 3-member committee has to be formed from them, the number of ways this can be done is given as:
4C3 = 4!/(4-3)!3!
4C3 = 41/3!
4C3 = 4 ways
Hence the number of combinations possible if a 3-member committee has to be formed from 2 teachers and 2 parents is 4 combinations
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