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Use the following information for questions 18 - 21. A 0.13 kg disk is rotating at an angular speed of 57 rad/s. The disk has a radius of 0.25 m. The disk speeds up for 3 s. After the 3 s have passed, the edge of the disk is under a centripetal force of 312.13 N. What is the centripetal acceleration of the disk at this time

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okpalawalter8

Answer:

[tex]a=2401m/s^2[/tex]

Explanation:

From the question we are told that:

Mass [tex]m=0.13kg[/tex]

Angular speed [tex]\omega=57rads/s[/tex]

Radius [tex]r=0.25m[/tex]

Time [tex]t=3s[/tex]

[tex]F=312.13N[/tex]

Generally the equation for centripetal acceleration is mathematically given by

[tex]a=\frac{f}{m}[/tex]

[tex]a=\frac{312.13}{0.13}[/tex]

[tex]a=2401m/s^2[/tex]

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