Answer:
[tex]\frac{N}{N_o} = 0.726 = 72.6\%[/tex]
Step-by-step explanation:
The following formula can be utilized for this question:
[tex]N = N_o (\frac{1}{2})^{\frac{t}{t_{1/2}} } \\\\\frac{N}{N_o} = (\frac{1}{2})^{\frac{t}{t_{1/2}} } \\\\[/tex]
where,
[tex]\frac{N}{N_o}[/tex] = ratio of the remaining amount to the original amount = ?
t = tme passed = 6 days
[tex]t_{1/2}[/tex] = half-life = 13 days
Therefore,
[tex]\frac{N}{N_o} = (\frac{1}{2} )^{\frac{6\ days}{13\ days} }\\\\[/tex]
[tex]\frac{N}{N_o} = 0.726 = 72.6\%[/tex]
