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Two factory plants are making TV panels. Yesterday, Plant A produced 5000 fewer panels than Plant B did. Five percent of the panels from Plant A and 3% of the panels from Plant B were defective. How many panels did Plant B produce, if the two plants together produced 1190 defective panels?

Respuesta :

Answer: 11,750

Step-by-step explanation:

Given

Plant A produces 5000 fewer panels than B

Suppose B produces x panels

[tex]\therefore A[/tex] produces x-5000 panels

A produces 5% defective that is

[tex]\Rightarrow d_a=(x-5000)\times 0.05[/tex]

B produces 3% defective that is ,

[tex]\Rightarrow d_b=x\times 0.03[/tex]

Total defective panels is 1190

[tex]\Rightarrow 1190=(x-5000)\times 0.05+0.03x\\\Rightarrow 1190=0.08x+250\\\Rightarrow 940=0.08x\\\Rightarrow x=11,750[/tex]

So, B produces 11,750 panels.

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