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Answer:   5005

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Explanation:

Let's say we had the slots A,B,C,D,E,F. Each slot represents where a flower would go.

For slot A, we have 15 different flowers to pick from.

Then slot B has 15-1 = 14 choices

C has 15-2 = 13 choices

and so on. We count our way down until we fill up slot F.

The count down looks like this: 15, 14, 13, 12, 11, 10

Multiply out those values: 15*14*13*12*11*10 = 3,603,600

If order mattered, then this represents the number of ways to select 6 flowers from a pool of 15 total.

However, order does not matter in this case. All that matters is the group overall.

For any group of 6 items, we have 6! = 6*5*4*3*2*1 = 720 different arrangements. That means the value 3,603,600 is too large exactly by a factor of 720.

We divide by 720 to get to (3,603,600)/720 = 5005 which is the final answer

It's the number of combinations where we select 6 from a pool of 15.

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As you can guess, you could use the nCr combination formula as an alternative route. Plug in n = 15 and r = 6 like so

[tex]_n C _r = \frac{n!}{r!*(n-r)!}\\\\_{15} C _{6} = \frac{15!}{6!*(15-6)!}\\\\_{15} C _{6} = \frac{15!}{6!*9!}\\\\_{15} C _{6} = \frac{15*14*13*12*11*10*9!}{6!*9!}\\\\_{15} C _{6} = \frac{15*14*13*12*11*10}{6!}\\\\_{15} C _{6} = \frac{15*14*13*12*11*10}{6*5*4*3*2*1}\\\\_{15} C _{6} = \frac{3,603,600}{720}\\\\_{15} C _{6} = 5005\\\\[/tex]

In the third to last step, notice how we have the 15*14*13*12*11*10 up top and 6*5*4*3*2*1 down below.

This value 5005 can be found in Pascal's Triangle. Look in the row that has 1, 15, ... and count out 7 spaces from the left. You should arrive at 5005. However, you'll need a fairly large Pascal's Triangle to use this method.

noproblemNP

Given:

Total number of flower cuts = 15 different flowers

Number of flowers Jeanine Baker wants to use = 6 flowers

To find:

Total number of ways 6 flowers can be chosen

Steps:

In this question, we need to find the total number of outcomes of choosing 6 random flowers from a total of 15 flowers

Let's give each flowers a letter, so there will be A, B, C, D, E, F, G, H, I, J, K, L, M, N and O.

Now let's find all the outcomes

Outcomes= ABCDEF, ABCDEG, ABCDEH, ABCDEI, ABCDEJ, ABCDEK, ABCDEL, ABCDEM, ABCDEN, ABCDEO.....

This method will take a lot of time so, i am going to use the formula

[tex]No.outcomes = \frac{n!}{r!(n-r)!}[/tex]

Here n = total number of items, and r = number of items chosen

Also the '!' means factorial, or the product of all positive numbers less then or equal to the number, so n! = n * (n-1) * (n-2) ..... * 1

So, now substituting the formula

[tex]No.outcomes = \frac{15!}{6! * (n-r)!}[/tex]

[tex]No.outcomes=\frac{15!}{6! * 9!}[/tex]

[tex]No.outcomes = \frac{15*14*13*12*11*10*9*8*7*6*5*4*3*2*1}{6*5*4*3*2*1*9*8*7*6*5*4*3*2*1}[/tex]

[tex]No.outcomes=\frac{15*14*13*12*11*10}{6*5*4*3*2*1}[/tex]          (cutting same numbers)

[tex]No.outcomes = \frac{7*13*3*11*10}{6}[/tex]                 (simplifying)

[tex]No.outcomes = \frac{30030}{6}[/tex]

[tex]No.outcomes=5005[/tex]

Therefore, the total number of ways the 6 flowers can be chosen is 5005 ways

Happy to help :)

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